Question 653234
a 3% salt solution is mixed with a 9% salt solution. how many grams of the 9% salt solution were used to make 150 g of a 4% salt solution?


Let amount of the 9% salt to be mixed be T
Since 150 g is to be made, then amount of 3% salt to be mixed = 150 – T


Equation:
Amount of 9% salt, plus amount of 3% salt equals 150 g of a 4% mixture, OR
.09(T) + .03(150 – T) = .04(150)
.09T + 4.5 - .03T = 6
.09T - .03T = 6 – 4.5 
.06T = 1.5


T, or amount of 9% salt to be mixed = {{{(1.5)/.06}}}, or {{{highlight_green(25)}}} g


Not needed:
Since total mixture is 150 g, then amount of 3% salt to be mixed = 150 – 25, or {{{highlight_green(125)}}} g 


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