Question 652858

let {{{x}}} be the larger of two numbers and {{{y}}} the smaller of two numbers

given:

The larger of two numbers is {{{5}}} less than {{{8}}} times the smaller,

so we have {{{x+5=8y}}}.....1

their sum is {{{94}}}, so {{{x+y=94}}}....2

solve the system:

{{{x+5=8y}}}.....1

{{{x+y=94}}}....2
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{{{x+5=8y}}}.....1.. solve for {{{x}}}

{{{x=8y-5}}}....substitute in 2


{{{8y-5+y=94}}}....2. solve for {{{y}}}

{{{9y=94+5}}}

{{{9y=99}}}

{{{y=99/9}}}

{{{highlight(y=11)}}}

now find {{{x}}}

{{{x=8*11-5}}}

{{{x=88-5}}}

{{{highlight(x=83)}}}