<PRE><B>Question 652695</B>
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Multiply either equation (BUT NOT BOTH) by -1.  Add the two equations.  Solve the result for *[tex \LARGE x].  Using the value for *[tex \LARGE x], substitute into either original equation and then calculate the value of *[tex \LARGE y]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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