Question 652694
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Hi,
Using the standard slope-intercept form for an equation of a line y = mx + b
  where m is the slope and b the y-intercept.
Line Through: (1,-4), parallel to y = -x + 3 ( m = -1) Slopes the same
New Line
 y = -x + b  ||Using pt(1,-4) to solve for b
-4 = -1 + b
 -3 = b 
y = -x - 3

Through: (2,1), perp. To y = 2x - 2 (m = 2) New Line, m = -1/2
New Line
 y = (-1/2)x + b  ||Using pt(2,1) to solve for b
 1 = -1 + b
 2 = b
  y = (-1/2)x + 2