<PRE><B>Question 652686</B>
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a.  Substitute the height value 18 for the variable representing height, *[tex \LARGE h], then put the equation into standard form and solve the factorable quadratic.  You will have two values, one is the time it will reach 18 feet on the way up and the other is the time it will be at 18 feet a second time on the way down.


b.  Substitute the height value 0 for the variable representing height (the height of the ground is zero), *[tex \LARGE h], then solve the factorable quadratic.  Discard the negative root because you don&#39;t care what happened &lt;b&gt;&lt;i&gt;before&lt;/i&gt;&lt;/b&gt; he threw the ball.  (Do you?!)


Check Stanbon&#39;s (above) arithmetic &lt;b&gt;&lt;i&gt;very&lt;/i&gt;&lt;/b&gt; carefully.  Both of these quadratics are factorable over the Rationals.
 

John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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