Question 652586
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
Parabolas:
the vertex form of a Parabola opening up(a>0) or down(a<0)is: {{{y=a(x-h)^2 +k}}} 
where(h,k) is the vertex 
the vertex form of a Parabola opening right(a>0) or left(a<0)is: {{{x=a(y-k)^2 +h}}}
 where(h,k) is the vertex 
Question states***
parabola opening to the left has a vertex at (-1, -3)
 x = a(y+3) - 1 , a <0   |Using  Pt(-3,-2) to solve for a
 -3 = a(-2 + 3)^2 - 1
 -2 = a
 x = -2(y+3) - 1
the coefficient of the squared term is -2
{{{drawing(300,300,   -6, 6, -6, 6,   grid(1),
circle(-1, -3,0.2),
circle(-3, -2,0.2),
graph( 300, 300, -6, 6, -6, 6,0,-3, sqrt((x+1)/-2)-3,-sqrt((x+1)/-2)-3  ))}}}