Question 652398


{{{10x^3(x-3)-5x(x-3)=0}}}

{{{(10x^3-5x)(x-3)=0}}}

{{{5x(2x^2-1)(x-3)=0}}}

solutions:


if {{{5x=0}}}...->...{{{x=0}}}


if {{{2x^2-1=0}}}...->...{{{2x^2=1}}}->...{{{x=sqrt(1/2)=1/sqrt(2)}}}..->


{{{x=1/sqrt(2)=1/1.41=0.709}}} or {{{x=-1/sqrt(2)=-1/1.41=-0.709}}}

so,{{{x=0.709}}} or {{{x=-0.709}}}


if {{{x-3=0}}}..->...{{{x=3}}}



{{{ graph( 600, 600, -7, 7, -30, 10, 10x^3*(x-3)-5x*(x-3)) }}}