<PRE><B>Question 652347</B>
rewrite log(x/x-1)-log(x/x+1)+log(x^2-1) as a single logarithm
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= log[((x/(x-1))*(x^2-1)) / (x/(x+1))]
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Cancel where you can to get:
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= log[((x)*(x+1)) / (x/(x+1))]
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Invert the denominator and multiply to get:
= log(1)
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= 0
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Cheers,
Stan H.
 </PRE>