Question 651881


The length {{{L}}} of a rectangle is {{{9 in}}} {{{more}}} than thr? width {{{W}}}. 

{{{L=W+9in}}}.....1

The perimeter {{{P}}} is {{{54in}}}. 

{{{P=2(L+W)}}}....2

{{{54in=2(L+W)}}}...plug in {{{L}}} from 1

{{{54in=2(W+9in+W)}}}...solve for {{{W}}}

{{{54in/2=W+9in+W}}}

{{{27in=2W+9in}}}

{{{27in-9in=2W}}}

{{{18in=2W}}}

{{{18in/2=W}}}

{{{highlight(9in=W)}}}

now find

{{{L=W+9in}}}.....1

{{{L=9in+9in}}}

{{{highlight(L=18in)}}}