Question 651806

let integers be {{{x}}} and {{{y}}}

given:

the difference of two integers is {{{18}}}

{{{x-y=18}}}.....1 

one integer is one-third of the other integer,

{{{y=(1/3)x}}}....2

solve this system:

{{{x-y=18}}}.....1

{{{y=(1/3)x}}}....2
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{{{x-y=18}}}.....1..plug in {{{y}}} from 2

{{{x-(1/3)x=18}}}....solve for {{{x}}}

{{{x-x/3=18}}}

{{{(3x-x)/3=18}}}

{{{2x/3=18}}}

{{{2x=18*3}}}

{{{2x=54}}}

{{{x=54/2}}}

{{{highlight(x=27)}}}

now find {{{y}}}

{{{y=(1/3)27}}}....2

{{{highlight(y=9)}}}