Question 651731
if segment {{{cd}}} bisects segment {{{rs}}}, but segment {{{rs}}} does {{{not}}} bisect {{{cd}}}, then segment {{{cd}}} and segment {{{rs}}} have only one point in common and it id end point of segment {{{rs}}} (either point r or point s lies is midpoint of segment {{{cd}}})

so, it is possible...


draw a line segment {{{rs}}} perpendicular at a point {{{r}}} or {{{s}}} on a line segment {{{cd}}}