Question 651454
Find the roots of the quadratic equation x^2 + 2x + 3 = 3x^2 + 2x - 1.
Combine like terms on the right
0 = 3x^2 - x^2 + 2x - 2x - 1 - 3
0 = 2x^2 - 4
4 = 2x^2
Divide both sides by 2
2 = x^2
x = +{{{sqrt(2)}}}
and
x = -{{{sqrt(2)}}}