Question 651399
Maricar is ten times older than her son Carl.
m = 10c
:
 In five years, the product of her age and her son's age two years ago will be 35.
(m+5)(c-2) = 35
replace m with 10c
(10c+5)(c-2) = 35
FOIL
10c^2 - 20c + 5c - 10 = 35
10c^2 - 15c - 10 - 35 = 0
10c^2 - 15c - 45 = 0
simplify, divide by 5
2c^2 - 3c - 9 = 0
Factors to
(2c+3)(c-3) = 0
the positive solution is all we want here
c = 3 yrs is Carl's present age
then
10(3) = 30 yrs is M's present age