Question 651423
{{{9*5^x=17*2^x}}}
start, by taking the log of both sides:
{{{log(9*5^x)= log(17*2^x)}}}
{{{log(9)+log(5^x)= log(17)+log(2^x)}}}
{{{log(9)+x*log(5)= log(17)+x*log(2)}}}
{{{x*log(5)= log(17)+x*log(2)-log(9)}}}
{{{x*log(5)-x*log(2)= log(17)-log(9)}}}
{{{x*log(5)-x*log(2)= log(17/9)}}}
{{{x(log(5)-log(2))= log(17/9)}}}
{{{x(log(5/2))= log(17/9)}}}
{{{x = log(17/9)/log(5/2)}}}
{{{x = log(17/9)/log(2.5)}}}
{{{x = .694}}}