Question 651092

let's {{{x}}} and {{{y}}} be the numbers

if the number {{{x}}} is eight less than twice the {{{y}}}, we have 

{{{x+8=2y}}}........1

if their sum is {{{100}}},we have

{{{x+y=100}}}...........2

now, we have to solve this system:

{{{x+8=2y}}}........1
-
{{{x+y=100}}}...........2
______________________ we can subtract 2 from 1

{{{x-x+8-y=2y-100}}}

{{{cross(x)-cross(x)+8-y=2y-100}}}

{{{8-y=2y-100}}}

{{{8+100=2y+y}}}

{{{108=3y}}}

{{{108/3=y}}}

{{{highlight(36=y)}}}...now find {{{x}}}

{{{x+y=100}}}...........2

{{{x=100-y}}}

{{{x=100-36}}}

{{{highlight(x=64)}}}