Question 651007
Call the sides of the square X.  The perimeter is the sum of the sides, or 4X.<P>
The rectangle's length is x+14 and width is x+10 (x extended the given lengths.)  Its perimeter is 2L + 2W = 2(x+14) + 2(x+10) = 2x+28+2x+20 = 4x + 48.<P>
The rectangle's perimeter (4x+48) is at least (meaning greater than or equal to) twice the perimeter of the square (2*4x).<P>
4x+48 >= 8x  Solve for x....subtract 4x from both sides.<P>
48 >= 4x   Divide both sides by 4:  12>=x.<P>
x can be 12 or less.