Question 650594
Find two solutions of each equation. Give your answers in degrees (0° &#8804; &#952; < 360°) and in radians (0 &#8804; &#952; < 2&#960;). Do not use a calculator. (Do not enter your answers with degree symbols.) a)sec(&#952;) = 2&#8730;3/3 b)sec(&#952;) = -2&#8730;3/3
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a) sec(&#952;) = 2&#8730;3/3
cos(&#952;) = 3/2&#8730;3=3&#8730;3/2*3=3&#8730;3/6=&#8730;3/2
(&#952;)=30 and 330 deg or &#960;/6 and 5&#960;/6 radians (in quadrants I and IV where cos and sec>0)
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b)sec(&#952;) = -2&#8730;3/3
cos(&#952;) =-&#8730;3/2
(&#952;)=150 and 210 deg or 5&#960;/6 and 7&#960;/6 radians (in quadrants II and III where cos and sec<0)