Question 650337
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Easier to write in terms of cents rather than 1/100 of a dollar:


The amount to pay on day *[tex \LARGE n] is *[tex \LARGE 2^n] cents.  By the way, the total amount she will have accumulated on day *[tex \LARGE n] is *[tex \LARGE \sum_{i\,=\,1}^n\,2^i\ =\ 2^{n\,+\,1}\ -\ 1] cents.


You will be paying $10,485.76 on the 20th day and she will have accumulated $20,971.51 after that payment.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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