Question 650164
Use the quadratic formula to solve {{{x^2-25x+10350=0}}} (you'll see why at the bottom)


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(-25)+-sqrt((-25)^2-4(1)(10350)))/(2(1))}}}


{{{x = (25+-sqrt(625-(41400)))/(2)}}}


{{{x = (25+-sqrt(-40775))/2}}}


{{{x = (25+sqrt(-40775))/2}}} or {{{x = (25-sqrt(-40775))/2}}}


{{{x = (25+5i*sqrt(1631))/2}}} or {{{x = (25-5i*sqrt(1631))/2}}}


Since we're getting complex solutions, this means that there is NO pair of real numbers that a) multiply to 10350 AND b) add to -25 at the same time