Question 59425


Simplify 3x^2y / sqrt(4x^4y^6)

Now sqrt(4x^4y^6) = sqrt(4)*sqrt(x^4)*sqrt(y^6)

                  = 2 (x^2) (y^3) [while finding the sqrt the exponent is halved.]

                  = 2(x^2)(y^3)

So 3x^2y / sqrt(4x^4y^6) = (3x^2y) / 2(x^2)(y^3)

                        = 3/(2y^2)   [While dividing the exponents get subtracted]


Good Luck!!!