Question 650130
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Hi,
Find the equation of the line that passes through the point (3,-6) and is parallel to the line 
3x+y-10=0    0r   y = -3x + 10
Using the standard slope-intercept form for an equation of a line y = mx + b
  where m is the slope and b the y-intercept. m = -3
parallel Lines have identical slopes
New Line
 y = -3x + b    | Using Ordered pair(x,y), Pt(3,-6) to solve for b
{{{-6 = -3*3 + b}}}
   3= b
 y = -3x +3    0r    3x + y = 3