Question 650120
the complementary angles add up to {{{90}}} degrees

{{{alpha+beta=90}}}

given:

angle {{{alpha}} which is {{{1/6}}} of {{{60}}} degrees:{{{alpha=(1/6)60=60/6=10}}}

so, {{{alpha=10}}}

plug it in {{{alpha+beta=90}}}  

{{{10+beta=90}}}.....solve for {{{beta}}}

{{{beta=90-10}}}

{{{beta=80}}}