Question 650018

{{{5x^3-18x^2+9x}}}

{{{x(5x^2-18x+9)}}}.....replace {{{-18x}}} with {{{-3x-15}}}

{{{x(5x^2-3x-15x+9)}}}....group

{{{x((5x^2-3x)-(15x-9))}}}

{{{x(x(5x-3)-3(5x-3))}}}

{{{x(x-3)(5x-3)}}}

now, if you set it equal to zero, you can solve for {{{x}}}

{{{x(x-3)(5x-3)=0}}}

roots:

{{{x=0}}} ........first solution


if {{{(x-3)=0}}}...->...{{{x=3}}}....second solution

if {{{(5x-3)=0}}}...->...{{{5x=3}}}..->...{{{x=3/5}}}..second solution