Question 59412
The given equations are:
-5x + 2y = 8
y = -3x + 26

Rearranging (adding 3x to both the sides of the above equation) we get..
3x + y = 26-------------(1)
-5x + 2y = 8---------------(2)

I choose to elimonate y.
(1) multiplied by 2 gives..    6x + 2y = 52 ------------(3)
                              -5x + 2y = 8  ------------(2)

eqn(3) - eqn (2) gives us..
6x + 2y -(-5x + 2y) = 52 - 8
==> 6x + 2y + 5x - 2y = 44  [Removing the parenthesis]
==> 11x = 44  [Adding the like terms]
==> x = 4 [dividing by 11 on both the sides]

Substituting x = 4 in eqn(1)  we get..
3(4) + y = 26
==> 12 + y = 26
==> y = 26 - 12 [subtracting 12 from both the sides of the equation]
==> y = 14

THus (x, y) = (4, 14)

Good Luck!!!