<PRE><B>Question 649730</B>
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The sum of the measures of two complementary angles is *[tex \LARGE 90^\circ], so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ +\ x\ +\ 8\ =\ 90]


Solve for *[tex \LARGE x], then calculate *[tex \LARGE 3x] and *[tex \LARGE x\ +\ 8]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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