Question 59407
    (i) y = x^3 ln3x
This is a product and we apply product rule.
dy/dx = x^3 (1/3x)(3) + ln3x * 3x^2 [Derivative of lnx = 1/x]
      = x^2 + 3x^2 ln3x [on simplifying]
      = x^2(1 + 3ln3x)

(ii) y = e^ln5x
       = 5x  [because e^lnx = x only]
dy/dx = 5


(iii) y = e^lnx
        = x
dy/dx = 1

(iv) I believe the question is y = [ln(5x+2)^3]/ln(5x+2)

                                 = 3ln(5x+2)/ln(5x+2) [property of ln]
                                 = 3
So dy/dx = 0

Good Luck!!!