Question 648315
tan of phata if the sin of phata is the square root of 7 divided by 6
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use x for phata
given: sinx=&#8730;7/6=opposite side/hypotenuse
adjacent side=&#8730;[6^2-(&#8730;7)^2]=&#8730;(36-7)=&#8730;29
tanx=opp side/adj side=&#8730;7/&#8730;26