Question 648841
{{{(a+b)^2 =  a^2 + 2ab + b^2}}}  by foil

Then a^2+2ab+b^2 = a^2+b^2, so  {{{2ab = 0}}}

So any choice for a,b must contain at least one zero.

One example:   a=0,  b=1.

Check:

(0+1)^2  = 0^2 + 1^2

1 = 1 TRUE

Any choice that satisfies a or b being 0 (or both) will give you a correct answer. Pick your favorite number and 0, and check it.