Question 648797
Please help me solve this question
its a wind current problem

it took the pilot an hour and a half to make a flight of 240 miles when flying against the headwind. The return trip took an hour and 12 minutes (the wind had not shifted nor changed its speed ) What was the speed of that wind?

please send me too an explanation please.
and thank you....
and fast if that's ok with you. thanks again ma'am/sir...


Let the speed in still air be S, and wind speed, W


Average speed during flight, against the wind = {{{240/1&1/2}}}, or {{{240/(3/2)}}}, or {{{240(2/3)}}}, or 160 mph. Therefore, S - W = 160 ----- eq (i)


Average speed during flight, with the wind = {{{240/1&12/60}}}, or {{{240/(6/5)}}}, or {{{240(5/6)}}}, or 200 mph. Therefore, S + W = 200 ----- eq (ii)


S - W = 160 ------ eq (i)
S + W = 200 ------ eq (ii)
- S + W = - 160 ------ Multiplying eq (i) by - 1 ----- eq (iii)
2W = 40 ------ Adding eqs (iii) & (ii)


W, or speed of wind = {{{40/2}}}, or {{{highlight_green(20)}}} mph


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