Question 648565
<pre>
    {{{M/(M+1)}}} < 1,  M &#8800; -1 

{{{M/(M+1)}}} - 1 < 0

Get an LCD of M+1

{{{
M/(M+1) - (M+1)/(M+1)}}} < 0

{{{(M-(M+1))/(M+1)}}} < 0

{{{(M-M-1)/(M+1)}}} < 0

{{{(-1)/(M+1)}}} < 0

The left side must be negative in order for
it to be less than 0.

Since the numerator is negative (-1), the denominator
must be positive.  "Positive" means "greater than 0",
so we set the denominator > 0

M + 1 > 0
    M > -1

That's the solution.

Edwin</pre>