Question 648231
Original equation: {{{17x(16x-144)=0}}}

Step 1: Distribute the '17x' to everything in the parenthesis

{{{17x(16x-144)=0}}}
{{{272x^2 - 2448x =0}}}

Step 2: Factor out an 'x' from the equation

{{{272x^2 - 2448x =0}}}
{{{x(272x - 2448) =0}}}

Step 3: Add '2448' to both sides so you can get '272x' by itself... also, drop the outer 'x' because that is automatically = 0... so, right now we know that one of our roots is {{{x=0}}}

{{{(272x - 2448) =0}}}
{{{(272x)=2448}}}

Step 4: Divide both sides by '272' to get 'x' by itself

{{{(272x)=2448}}}
{{{(x)=9}}

So we have the outer 'x', which is = 0, and the other root is {{{x = 9}}}

So.. the roots of this equation are {{{x=0}}} and {{{x=9}}}