Question 648161
Original equation: {{{t^3+8}}}

To factor sum of cubes, you need to use the following formula:

{{{a^3 + b^3 = (a + b)(a^2 - ab + b^2)}}}

The {{{a^3}}} in your equation is {{{t^3}}} and the {{{b^3}}} in your equation is {{{2^3=8}}}

Step 1: Replace variables in formula with what is given

Original equation: {{{t^3+8}}}
Formula: {{{a^3 + b^3 = (a + b)(a^2 - ab + b^2)}}}

{{{a^3 + b^3 = (t + 2)(t^2 - 2t + 4)}}}

So the factored version of the equation you provided is: {{{(t + 2)(t^2 - 2t + 4)}}}