Question 59257
135X^2-222X+91=0
USING THE QUADRATIC EQUATION X=(-B+-SQRT[B^2-4AC])/2A WE GET

X=(222+-SQRT[222^222-4*135*91])/2A
X=(222+-SQRT[49,284-49,140])/270
X=(222+-SQRT[144])/270
X=(222+-12)/270
X=210/270
X=.777777
X=234/270
X=.866666

6X^2-42X+72=0
X^2-7X+12=0
(X-4)(X-3)=0
X-4=0
X=4
X-3=0
X=3