Question 647763
Graph a parabola: Give the vertex,axis,range and domain. I am lost as to how to set these problems up. It has been 20 years since I was in school. Here is the problem: 
f(x)=x^2+10x+23
This is an equation of a parabola that opens upwards. (sign of lead coefficient>0)
Its standard form: (y=(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex.
Complete the square:
f(x)=(x^2+10x+25)+23-25
f(x)=(x+5)^2-2
vertex: (-5,-2)
axis of symmetry: x=-5
Range: (-2,∞)
Domain: (-∞,∞)
see graph below:

{{{ graph( 300, 300, -10, 10, -10, 10,x^2+10x+23) }}}