Question 647772

write an equation of a line containing the given point (8,-6) parallel to 2x-3y=7


2x - 3y = 7


- 3y = - 2x + 7


{{{y = (- 2/-3)x + 7/-3}}}


{{{y = (2/3)x - 7/3}}}


Since the lines are parallel, then the equation will have the same slope of m = {{{2/3}}}. Point = (8, - 6)


{{{y - y[1] = m(x - x[1])}}} ------- Point-slope formula


{{{y - - 6 = (2/3)(x - 8)}}} ------- Applying the point-slope formula


{{{y + 6 = (2/3)x - (2/3)8}}}


{{{y = (2/3)x - 16/3 - 6}}}


{{{y = (2/3)x - 16/3 - 18/3}}}


{{{highlight_green(y = (2/3)x - 34/3)}}}


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