Question 647744

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-1,1\right)]. So this means that {{{x[1]=-1}}} and {{{y[1]=1}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(2,3\right)].  So this means that {{{x[2]=2}}} and {{{y[2]=3}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(3-1)/(2--1)}}} Plug in {{{y[2]=3}}}, {{{y[1]=1}}}, {{{x[2]=2}}}, and {{{x[1]=-1}}}



{{{m=(2)/(2--1)}}} Subtract {{{1}}} from {{{3}}} to get {{{2}}}



{{{m=(2)/(3)}}} Subtract {{{-1}}} from {{{2}}} to get {{{3}}}



So the slope of the line that goes through the points *[Tex \LARGE \left(-1,1\right)] and *[Tex \LARGE \left(2,3\right)] is {{{m=2/3}}}