Question 647767
We're going to factor this equation by using the zero-product principle, which means we will be setting the entire equation equal to zero.

Step 1: You can factor out a 5 and an 'n' from each of the factors.
{{{5n^2-5n=0}}}

The equation now becomes:

{{{5n^2-5n=0}}}
{{{5n(n-1)=0}}}

Step 2: Set everything on the outside and inside of the equation equal to zero.

{{{5n = 0}}} and {{{(n-1) = 0}}}

Step 3:

For {{{5n = 0}}}, divide 5 on both sides to get 'n' by itself. When you do that, you're going to get n = 0. This is ONE answer.

Step 4: For {{{(n-1) = 0}}}, add 1 to both sides to get 'n' by itself. When you do that, you're going to get n = 1. This is the SECOND answer.

Step 5: Your answers are n = 0 and n = 1