Question 647495

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(8,5\right)]. So this means that {{{x[1]=8}}} and {{{y[1]=5}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(0,20\right)].  So this means that {{{x[2]=0}}} and {{{y[2]=20}}}.



{{{d=sqrt((x[1]-x[2])^2+(y[1]-y[2])^2)}}} Start with the distance formula.



{{{d=sqrt((8-0)^2+(5-20)^2)}}} Plug in {{{x[1]=8}}},  {{{x[2]=0}}}, {{{y[1]=5}}}, and {{{y[2]=20}}}.



{{{d=sqrt((8)^2+(5-20)^2)}}} Subtract {{{0}}} from {{{8}}} to get {{{8}}}.



{{{d=sqrt((8)^2+(-15)^2)}}} Subtract {{{20}}} from {{{5}}} to get {{{-15}}}.



{{{d=sqrt(64+(-15)^2)}}} Square {{{8}}} to get {{{64}}}.



{{{d=sqrt(64+225)}}} Square {{{-15}}} to get {{{225}}}.



{{{d=sqrt(289)}}} Add {{{64}}} to {{{225}}} to get {{{289}}}.



{{{d=17}}} Take the square root of {{{289}}} to get {{{17}}}.



So our answer is {{{d=17}}} 



So the distance between the two points is  17 units. 


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