Question 647432


  for {{{f(x)=1/(x-12)}}} and {{{g(x)=x+3}}}

{{{f(g(x))}}} is: replace every {{{x}}} in {{{f(x)}}} with {{{g(x)=x+3}}}

{{{f(g(x))=1/((x+3)-12)=1/(x+3-12)=1/(x-9)}}}