Question 647385
A diagonal line divides the rectangle in two shape of "right-angle triangle"
So the diagonal = 'hypotenuse' of the right-angle triangle = 14ft
and the width = the 'opposite' of the right-angle triangle = 6ft (that is taking into account down part of the rectangle after dividing it)

Now, the question becomes a problem of trigonometry - 'square of hypotenuse' is equal to 'sum square of both the opposite and the adjacent'; {{{H^2 = O^2 + A^2}}}

=> H = 14ft, O = 6ft and we look for A
=> {{{H^2 = O^2 + A^2}}}
{{{14^2 = 6^2 + A^2}}}
{{{196 = 36 + A^2}}}
{{{196 - 36 = A^2}}}
{{{160 = A^2}}}
Then by taking square root of  both sides: {{{A^2}}} will become 'A' and 160 will be {{{sqrt(160)}}}

=> {{{sqrt(160) = A}}}
{{{12.649 = A}}}
Hence, A = 12.649, so approximately the length of the other side is 12.6ft