Question 647326


{{{12x=4y+28}}}

{{{12x-28=4y}}}

{{{12x/4-28/4=y}}}

{{{3x-7=y}}}

find {{{x-intercept}}} and {{{y-intercept}}}

set {{{y=0}}} and solve for {{{x}}}

{{{3x-7=0}}}.....->...{{{3x=7}}}->...{{{x=7/3}}}->...{{{x=2.33}}}

the {{{x-intercept}}} is at ({{{2.33}}},{{{0}}})

set {{{x=0}}} and solve for {{{y}}}

{{{3*0-7=y}}}.....->...{{{-7=y}}}

the {{{y-intercept}}} is at ({{{0}}},{{{-7}}})

now graph it:

{{{ graph( 600, 600, -10, 10, -10, 10, 3x-7) }}}