Question 647370

let’s number be {{{x}}}

given:

The number is less than {{{30}}}. 

{{{x<10}}}

the number is an even number

The sum of the digits is {{{10}}}. 

the digits are {{{1}}},{{{2}}},{{{3}}},{{{4}}},{{{5}}},{{{6}}},{{{7}}},{{{8}}} and {{{9}}}


The sum of the {{{1+9=10}}}, {{{2+8=10}}}, {{{3+7=10}}} and {{{4+6=10}}}...which one could be?

let's find it out doing elimination:

The sum of the {{{1+9=10}}}...it could be number {{{19}}} and {{{91}}}...eliminate {{{19}}} because the number is {{{NOT}}} an {{{even}}}
 number,and eliminate {{{91}}} because the number is {{{NOT}}} less than {{{30}}}

The sum of the {{{2+8=10}}}..it could be number {{{28}}} and {{{82}}}...eliminate {{{82}}} because the number is {{{NOT}}} less than {{{30}}}

The sum of the {{{3+7=10}}}..it could be number {{{37}}} and {{{73}}}...eliminate {{{both}}} because they are {{{NOT}}} less than {{{30}}}

The sum of the {{{4+6=10}}}..it could be number {{{46}}} and {{{64}}}...eliminate {{{both}}} because they are {{{NOT}}} less than {{{30}}}

So, the number could be {{{only}}} a number {{{28}}} because it is an {{{even}}} number, and it is less than {{{30}}} .