Question 647273
[x^(4/3)*y^(2/3)]/xy^(1/3)
[x^(4/3)*y^(2/3)]/x^(1/3)y^(1/3)
[x^(4/3)*y^(2/3)]*x^(-1/3)y^(-1/3)
x^(4/3)*y^(2/3)*x^(-1/3)*y^(-1/3)
x^(4/3)*x^(-1/3)*y^(2/3)*y^(-1/3)
x^(-4/9)*y^(-2/9)