Question 647203
You must first get it into the form:
ax^2+bx+c=0

Then, for ax2 + bx + c = 0, the value of x is given by:

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}


So:
(9x-1)(2x+1)=2x
18x^2+7x-1=2x
18x^2+5x-1=0

Then substitute a, b and c into the quadratic formula:
  
{{{x = (-5 +- sqrt( 5^2-4*18*-1 ))/(2*18) }}}