Question 647192
Hi, my name is Aaron I am in 10th grade and im in honors trig/pre-calc.

Lets call a side of square A (the smaller square) X.
Lets call a side of square b (the bigger square) Y.

Lets set up a system of equations.

Since we know one side of square B is 6 bigger, we can say

x+6=y

also we know the area of them added together is 596

x^2+y^2=596


substitute y=x+6 into the equation above

x^2+ (x+6)^2=596

foil...

x^2+x^2 +12x+36=596

simplify it down

2x^2+12x=560
x^2+6x-280=0

now plug into quadratic formula


result: x= 14 or-20

since distance cant be positive x has to be 14. we now know the sides of square A is 14

so plug back into y=x+6 to find the side length of square b

y=20

multiply by 4, because a square has 4 sides, so we can find permitter. 

Square B's permitter is 80units.

Hope this helped. Please leave me positive feedback, this took over 20 mins to type