Question 646857
A plane rises from take-off and flies at an angle of 10 degrees with the
 horizontal runway. 
When it has gained 500 feet of altitude, find the distance, to the nearest
 foot, the plane has flown.
:
This can be solved using the sine of 10 degrees, 
side opposite is 500 ft
hypotenuse = slant distance (s) flown by the plane
sin(10) = {{{500/s}}}
s = {{{500/sin(10)}}}
s = 2,879 ft flown by the plane to reach 500 ft alt