Question 646824
I guess you have this:

{{{x^-1/(x^-2+y^-2)}}}


={{{(1/x)/((1/x^2)+(1/y^2))}}}


={{{(1/x)/((y^2+x^2)/(y^2*x^2)))}}}


={{{(y^2*x^2)/(x(y^2+x^2))}}}


={{{(y^2*x^cross(2))/(cross(x)(y^2+x^2))}}}



={{{(y^2*x)/(y^2+x^2))}}}



roots:

{{{x=0}}} , {{{y}}}≠ {{{0}}}

{{{y=0}}}   {{{x}}}≠ {{{0}}}