Question 646689
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
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cone with s = 3in and base area of {{{A = pi*r^2 =16*pi }}}in^2, r = 4in
surface area = {{{pi*r^2 + pi*r*s = 16pi + pi*4*3 = 16pi + 12pi = 28pi}}}in^2