Question 646673
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
{{{ 4x-8 sqrt( x )-5=0 }}}   || Let {{{y = sqrt(x)}}}
   4y^2 - 8y - 5 = 0
  (2y - 5)(2y + 1) = 0
  y = 5/2  or y = -1/2   Tossing out y = -1/2 as being an extraneous root
 y = 5/2 and {{{x = 25/4 = 6.25}}}

{{{drawing(300,300,   -6, 10, -6, 6,  grid(1),
circle(0, 6.25,0.3),
graph( 300, 300, -6, 10, -6, 6,0,4x-8sqrt(x)-5))}}}