Question 59111
Factor {{{27x^3-8y^3}}}
The formula for factoring the difference of cubes is:{{{highlight(u^3-v^3=(u-v)(u^2+uv+v^2))}}}
{{{27x^3-8y^3=(3x)^3-(2y)^3}}}  u=3x and v=2y
{{{(3x-2y)((3x)^2+(3x)(2y)+(2y)^2)}}}
{{{highlight((3x-2y)(9x^2+6xy+4y^2))}}}
Happy Calculating!!!